isLexCompatiblyGVD(I, L)
An ideal $I$ is $<$-compatibly geometrically vertex decomposable if there exists a (lexicographic) order $<$ such that $I$ is geometrically vertex decomposable and for every (one-step) geometric vertex decomposition, we pick $y$ to be the most expensive indeterminate remaining in the ideal according to $<$ [KR, Definition 2.11]. For the definition of a (one-step) geometric vertex decomposition, see oneStepGVD.
This method returns a Boolean value depending upon whether or not the given ideal is $<$-compatibly geometrically vertex decomposable with respect to a given ordering lex ordering of the indeterminates. Compare this function to the command findLexCompatiblyGVDOrders which checks all possible lex orders of the variables in order to find at least one $<$-compatibly lex order.
Below is [KR, Example 2.16], which is an example of an ideal that is not $<$-compatibly geometrically vertex decomposable. Any permutation of the variables we give in this example will result in false.
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In view of [KR, Proposition 2.14], we check whether the initial ideal ${\rm in}_<(I)$ is $<$-compatibly geometrically vertex decomposable. Heuristically, one should expect this check to be quicker than the definition [KR, Definition 2.11] since checking unmixedness (that is, computing a primary decomposition) is in general faster for monomial ideals.
[KR] Patricia Klein and Jenna Rajchgot. Geometric vertex decomposition and liaison. Forum Math. Sigma, 9 (2021) Paper No. e70, 23pp.
The object isLexCompatiblyGVD is a method function with options.
The source of this document is in GeometricDecomposability.m2:1326:0.